fs: ext4: return NULL instead of 0

ext4fs_get_extent_block() returns a pointer, so return NULL instead of
integer 0.

Signed-off-by: Sascha Hauer <s.hauer@pengutronix.de>

1 files changed, 2 insertions, 2 deletions

diff --git a/fs/ext4/ext4_common.c b/fs/ext4/ext4_common.c
index 2703b55e99..c9f27f1278 100644
--- a/fs/ext4/ext4_common.c
+++ b/fs/ext4/ext4_common.c
@@ -52,7 +52,7 @@ static struct ext4_extent_header *ext4fs_get_extent_block(struct ext2_data *data
 		index = (struct ext4_extent_idx *)(ext_block + 1);
 
 		if (le16_to_cpu(ext_block->eh_magic) != EXT4_EXT_MAGIC)
-			return 0;
+			return NULL;
 
 		if (ext_block->eh_depth == 0)
 			return ext_block;
@@ -64,7 +64,7 @@ static struct ext4_extent_header *ext4fs_get_extent_block(struct ext2_data *data
 		} while (fileblock >= le32_to_cpu(index[i].ei_block));
 
 		if (--i < 0)
-			return 0;
+			return NULL;
 
 		block = le16_to_cpu(index[i].ei_leaf_hi);
 		block = (block << 32) + le32_to_cpu(index[i].ei_leaf_lo);