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| author | Pranith Kumar <bobby.prani@gmail.com> | 2014-09-02 23:34:29 -0400 |
|---|---|---|
| committer | Paul E. McKenney <paulmck@linux.vnet.ibm.com> | 2014-11-13 10:34:55 -0800 |
| commit | 8ab8b3e1837fc580b30263ed3c44dc34798714d9 (patch) | |
| tree | 022a2c06647baed2a353c56399d84a62caa0f648 /Documentation/memory-barriers.txt | |
| parent | 1f7870dd8729c64b8472b42440811e7ff94d16a4 (diff) | |
| download | linux-0-day-8ab8b3e1837fc580b30263ed3c44dc34798714d9.tar.gz linux-0-day-8ab8b3e1837fc580b30263ed3c44dc34798714d9.tar.xz | |
documentation: memory-barriers.txt: Correct example for reorderings
Correct the example of memory orderings in memory-barriers.txt
Commit 615cc2c9cf95 "Documentation/memory-barriers.txt: fix important typo re
memory barriers" changed the assignment to x and y. Change the rest of the
example to match this change.
Reported-by: Ganesh Rapolu <ganesh.rapolu@hotmail.com>
Signed-off-by: Pranith Kumar <bobby.prani@gmail.com>
Signed-off-by: Paul E. McKenney <paulmck@linux.vnet.ibm.com>
Diffstat (limited to 'Documentation/memory-barriers.txt')
| -rw-r--r-- | Documentation/memory-barriers.txt | 22 |
1 files changed, 11 insertions, 11 deletions
diff --git a/Documentation/memory-barriers.txt b/Documentation/memory-barriers.txt index 1073e019ef061..f7fa63508abac 100644 --- a/Documentation/memory-barriers.txt +++ b/Documentation/memory-barriers.txt @@ -121,22 +121,22 @@ For example, consider the following sequence of events: The set of accesses as seen by the memory system in the middle can be arranged in 24 different combinations: - STORE A=3, STORE B=4, x=LOAD A->3, y=LOAD B->4 - STORE A=3, STORE B=4, y=LOAD B->4, x=LOAD A->3 - STORE A=3, x=LOAD A->3, STORE B=4, y=LOAD B->4 - STORE A=3, x=LOAD A->3, y=LOAD B->2, STORE B=4 - STORE A=3, y=LOAD B->2, STORE B=4, x=LOAD A->3 - STORE A=3, y=LOAD B->2, x=LOAD A->3, STORE B=4 - STORE B=4, STORE A=3, x=LOAD A->3, y=LOAD B->4 + STORE A=3, STORE B=4, y=LOAD A->3, x=LOAD B->4 + STORE A=3, STORE B=4, x=LOAD B->4, y=LOAD A->3 + STORE A=3, y=LOAD A->3, STORE B=4, x=LOAD B->4 + STORE A=3, y=LOAD A->3, x=LOAD B->2, STORE B=4 + STORE A=3, x=LOAD B->2, STORE B=4, y=LOAD A->3 + STORE A=3, x=LOAD B->2, y=LOAD A->3, STORE B=4 + STORE B=4, STORE A=3, y=LOAD A->3, x=LOAD B->4 STORE B=4, ... ... and can thus result in four different combinations of values: - x == 1, y == 2 - x == 1, y == 4 - x == 3, y == 2 - x == 3, y == 4 + x == 2, y == 1 + x == 2, y == 3 + x == 4, y == 1 + x == 4, y == 3 Furthermore, the stores committed by a CPU to the memory system may not be |